E0259: '.' is not allowed after generic arguments

In TypeScript types, you can look up a property of a generic type using Type<Arg>["name"] syntax. It is a syntax error to instead use . to look up a property of a generic type:

class Thing<T> {
  static thong: number;
}
type ThingThong<T>
  = typeof Thing<T>.thong;

To fix this error, write ["name"] instead of .name:

class Thing<T> {
  static thong: number;
}
type ThingThong<T>
  = typeof Thing<T>["thong"];

Introduced in quick-lint-js version 2.7.0.

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