E0124: cannot declare variable named keyword
It is a syntax error to declare a variable named certain keywords like
debugger
or while
:
function parseVar(s) {
let var = s.split()[0];
let value = s.split()[1];
return {var, value};
}
To fix this error, pick a different variable name:
function parseVar(s) {
let varName = s.split()[0];
let value = s.split()[1];
return {varName, value};
}
Introduced in quick-lint-js version 0.2.0.